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2a^2=81
We move all terms to the left:
2a^2-(81)=0
a = 2; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·2·(-81)
Δ = 648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{648}=\sqrt{324*2}=\sqrt{324}*\sqrt{2}=18\sqrt{2}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{2}}{2*2}=\frac{0-18\sqrt{2}}{4} =-\frac{18\sqrt{2}}{4} =-\frac{9\sqrt{2}}{2} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{2}}{2*2}=\frac{0+18\sqrt{2}}{4} =\frac{18\sqrt{2}}{4} =\frac{9\sqrt{2}}{2} $
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